in the given figure ABCD is a parallelogram AE perpendicular to DC and CF perpendicular to AD. If AB =16cm, AE =8cm, CF=10cm .Find AD Explain
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8
we know that to find area of parallelogram the formula is base X height
now, AE ×DC = 16×8
AD ×CF = AD ×10
BECAUSE THE AREA WILL BE THE SAME
EQUATING BOTH
AE × DC = AD× CF
16×8 = AD× 10
AD = 16×8/10
AD = 128/10
AD = 12.8 CM
PLS MARK AS BRAINALIST ANSWER PLS
now, AE ×DC = 16×8
AD ×CF = AD ×10
BECAUSE THE AREA WILL BE THE SAME
EQUATING BOTH
AE × DC = AD× CF
16×8 = AD× 10
AD = 16×8/10
AD = 128/10
AD = 12.8 CM
PLS MARK AS BRAINALIST ANSWER PLS
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4
Question :-
In figure, ABCD is a parallelogram, AE ⊥ DC and CF ⊥ AD. If AB = 16 cm, AE = 8 cm and CF = 10 cm, find AD.
Answer :-
We have, AE ⊥ DC and AB = 16 cm
∵ AB = CD [Opposite sides of parallelogram]
∴ CD = 16 cm
Now, area of parallelogram ABCD = CD x AE
= (16 x 8) cm2 = 128 cm2 [∵ AE = 8 cm]
Since, CF ⊥ AD
∴ Area of parallelogram ABCD = AD x CF
⇒ AD x CF = 128 cm
⇒ AD x 10 cm = 128 cm2 [∵ CF= 10 cm]
⇒ AD = 128/10 cm = 12.8 cm 10
Thus, the required length of AD is 12.8 cm
Hope it helps ❤ Mrk as brainliest
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