Question

In the given figure, ABCD is a parallelogram and BE is perpendicular to AD. If BE=14cm and AD=8cm, find
the area of triangle DBC=_​

Answer 1

Answer. 15 cm explanation

Answer 2

The area of triangle DBC=56 square cm

Step-by-step explanation:

In parallelogram ABCD

BE=14 cm

AD=8 cm

Area of parallelogram ABCD=$Base\times height$

Using the formula

Area of parallelogram ABCD=$AD\times BE=14\times 8=112 cm^2$

We know that when a triangle is  formed on the same base  and between parallel lines of parallelogram

Then, area of triangle=$\frac{1}{2}\times area of parallelogram$

Using the formula

Area of triangle ABD=$\frac{1}{2}{\times 112=56cm^2$

Area of triangle C=Area of parallelogram ABCD-area of triangle ABD=112-56=56cm^2[/tex]

Hence, the area of triangle DBC=56 square cm

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