Question

In the given figure, ABCD is a parallelogram and T is the mid-point of AD. ar(quadrilateral ABCT)=45 cm², then find ar (Triangle TCD).​

Answer 1

Step-by-step explanation:

In ||gm ABCD,

∆TCD and ||gm ABCD are on same base CD and between same parallel AB and CD,

so,Ar(∆TCD)=1/2Ar(||gm ABCD)

Ar(∆TCD)=1/2×45

Hence,Ar(∆TCD)=22.5 cm².

Answer 2

Answer:

In ||gm ABCD,

∆TCD and ||gm ABCD are on same base CD and between same parallel AB and CD,

so,Ar(∆TCD)=1/2Ar(||gm ABCD)

Ar(∆TCD)=1/2×45

Hence,Ar(∆TCD)=22.5 cm².