Question

in the given figure ABCD is a parallelogram angle ADE =50° and angle ACE = angle BED = 90° the value of angle EAC + angle ABC -2 angle DAC is

Answer 1

50°.......................

Answer 2

∠BED = 90° ∴ ∠AEC = 45°

Then ∠EAC = 45° , ∠EAB = 45°

∠ABC = 45°

∠ADE = 50° ,  Then ∠DAC = 40°

∠EAC+∠ABC-2.∠DAC =  45° +45°-2×40°

                                      = 90°-80° = 10°