In the given figure, ABCD is a parallelogram. D
ar (AADP)= 15 cm² and ar (AAPC)= 20 cm, find
ar (AAPB).
(Hint: ar (AADP) + ar (AAPC)= 15 cm2 + 20 cm2
= 35 cm
– ar (AADC) = 35 cm2
B
: ar(|| gm ABCD) = 2 x 35 cm² = 70 cm?
(::: If a triangle and a parallelogram are on the same base
between the same parallel lines, then area of
triangle is half of the area of the parallelogra
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Answer:
Answer
{ 81^-¾ × 16¼ × 6² × 27^4/3 }⅓
= (3⁴)^-¾ × (2⁴)¼ × 6² × (3³)⁴/3 }⅓
= {3^-³ × 2¹ × 6² × 3⁴ } ⅓
= {3^-³ × 2 × 2² × 3² × 3⁴ } ⅓
= { 3^-³ × 2³ × 3⁶ }⅓
= { 2³ × 3³ }⅓
= (6³)⅓
= 6¹
= 6
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