Question

in the given figure ABCD is a parallelogram F is midpoint of AD join BF and entered into the intersects CDproduce at a show that area of BDE is equal to area of CFE​

Answer 1

Step-by-step explanation:

Now, BC∥EF

⇒AD∥EF [∵BC∥AD as ABCD is a ∥

gm

]

⇒AEFD is a parallelogram

⇒AE=GP ...(ii)

But, E is the mid-point of AB.

∴AE=BE

⇒GP=PH [Using (i) and (ii)