Question

in the given figure ABCD is a parallelogram find the value of a, b, c, d.
Please give me answer.​

Answer 1

Case 1:

a = 115 deg because it is equal to <AOB by VOA

In triangle ODC:

the exterior angle (140 deg) = a+b

                                          140 = 115+b

                                           b    = 25 deg

By ASP in triangle ODC:

    a+b+c = 180

   115+25+c = 180

       c = 40 deg

d = 50 deg by alternate angles since AD||BC (ABCD is a ||gm)

Case 2:

In triangle CBD by ASP:

   3a+7a+2a = 180

             12a  = 180

                 a = 15 deg

c = 7a since opp. angles in a ||gm are equal

i.e c = 7(15) = 105 deg

b = 3a by alternate angles since ABCD is a ||gm

i.e b = 3(15) = 45 deg

d = 2a by alternate angles since ABCD is a ||gm

i.e d=2(15) = 30 deg

Hope it solves ur doubt

Bye