Question

in the given figure, ABCD is a parallelogram. find x,y,z​

Answer 1

༺ศསຮཡཛཞ༻

From the figure

AD∥BC,BD is the transversal line

⟹∠ADB=∠DBC (∵alternate angles)

⟹z=30

∘

Also

100

∘

,x are supplementary angles

So x=180

∘

−100

∘

=80

∘

x,y,30

∘

forms a triangle

⟹x+y+30

∘

=180

∘

⟹y=180

∘

−80

∘

−30

∘

=70

∘

HOPE THIS HELPS YOU

PLZ MARK AS THE BRAINLIEST......... :-)

Answer 2

From the figure
AD||BC,BD is a transversal line
=>angle ADB=angle DBC ( alternate angle )
=>z=30*
Also
100*,X are supplementary angles
So,X=180*–100*=80*
X,Y,30* forms triagnle
=> X+Y +30*=180*
=> Y=180*–80*–30*=70