Question

In the given figure ABCD is a parallelogram. find x,y,z​

Answer 1

From the figure

AD∥BC,BD is the transversal line

⟹∠ADB=∠DBC (∵alternate angles)

⟹z=30

∘

Also

100

∘

,x are supplementary angles

So x=180

∘

−100

∘

=80

∘

x,y,30

∘

forms a triangle

⟹x+y+30

∘

=180

∘

⟹y=180

∘

−80

∘

−30

∘

=70

∘