Question

In the given figure ABCD is a parallelogram if ar(ABCD)
66 cm^2 BF = BD, then ar(
BFC) is
​

Answer 1

Given :  ABCD is a parallelogram

Ar(ABCD)  = 66 cm²

BF = BD

To Find : Ar (ΔBFC)

Solution:

Diagonal Divided parallelogram in two equal area triangle

=> Ar(ΔABD) =  Ar(ΔBCD) = Ar(ABCD)  /2

=>  Ar(ΔABD) =  Ar(ΔBCD) = 66 /2

=>  Ar(ΔBCD)  = 33 cm²

BD = BF

=> D is mid point of DF

Hence CB is median of ΔBFC

Median Divides triangle in 2 Equal area

Hence

Ar  (ΔBFC)   =  Ar(ΔBCD)

=> Ar  (ΔBFC)   = 33 cm²

Ar  (ΔBFC)  is 33 cm²

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