Question

in the given figure ABCD is a parallelogram in which angle OCB is equal to 25 degree and Angle OAB equal to 45 degree.. find angle DAB ,angle DCO and angle ABC​

Answer 1

Answer:

angle DAB = 70°

angle DCO= 45°

angle ABC= 110°

Step-by-step explanation:

Since AB||DC and AC transversal

angle DAO = angle OCB. ( alternate angles)

angle DAO = 25°

angle DAB = angle DAO + angle OAB

= 25°+45°

= 70°

Again, angle DCO = angle OAB (alternate angle)

angle DCO = 45°

Considering triangle ABC,

angle OAB + angle ABC + angle OCB = 180°

45°+ angle ABC + 25°= 180°

angle ABC = 180°-70°

angle ABC = 110°

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Answer 2

Answer

The Answer Is -

Angle DCO- 45

Angle DAB- 70

Angle ABC- 110

Explanation

Given - ABCD Is A Parallelogram In Which AB||DC, AD||BC

And AC And BD Is Transversal.

To Prove That - Angle DCO , Angle ABC , Angle DAB .

Prove -

In Parallelogram ABCD,

AB || DC ( Given )

And AC Is Transversal ( Given)

So , Angle CAB = Angle ACD ( Alternate Angles)

So Angle ACD = 45

Or, Angel DCO = 45

In Parallelogram ABCD

AD || BC ( Given )

BD Is Transversal ( Given )

•°• Angle ACB = Angle DAC ( Alternate Angles)

Angle ACB = 25

Angle DAC = 25

Then ,

Angle DAB = Angle DAC + Angle CAB ( AC Is Transversal )

Angle DAB = 25 + 45

Angle DAB = 70

In Triangle ABC

Angle CAB+Angle ACB+Angle ABC = 180 (Angle Some Property)

45 + 25 + Angle ABC = 180

Angle ABC = 180 - 70

Angle ABC = 110

Answer Is Complete !

( Note - Sum Of All Angles Of Parallelogram s 360 You Can Add These Angle To Check These Answer )

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