Question

In the given figure, ABCD is a parallelogram in which
DAB = 70° and Z DBC = 65°, then find the measure
of ZCDB.​

Answer 1

Step-by-step explanation:

∠A + ∠B = 180°

⇒ 70° + ∠B = 180°

⇒ ∠B = 110°  

⇒  ∠ABD + ∠DBC = 110°  

⇒ ∠ABD + 65° = 110°

⇒ ∠ABD  = 45°

Now, ∠CDB = ∠ABD = 45

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