In the given figure, ABCD is a parallelogram in which /_DAC = 30°, /_ADB = 40° and angle /_ABD = 25°. Find the measures of the angles of the DOC.
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in triangle AOD
angle OAD + angle ADO+ angle DOA=180°
30+40+angle DOA=180°
angle DOA=180-70=110°
angle DOA+angle DOC=180°(LP)
110+angle DOC=180
angle DOC=180-110=70°
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angle OAD + angle ADO+ angle DOA=180°
30+40+angle DOA=180°
angle DOA=180-70=110°
angle DOA+angle DOC=180°(LP)
110+angle DOC=180
angle DOC=180-110=70°
hope it helps you
mark as the brainliest
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