Math, asked by singhkushwahaayush0, 4 days ago

In the given figure, ABCD is a parallelogram in which ZDAC = 30°, ZADB = 40° and ZABD = 25°. Find the measures of the angles of the ADOC.



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Answers

Answered by dk7110088
2

Answer:

Correct option is A 0 ZADB + ZDBA + ZBAD = 180º angles of triangle is 180 ° ] 40 ° + 30 ° + ZBAD 70 ° + ZBAD = 180 ° ZBAD = 110⁰ ZBAD = ZDCB of parallelogram ] angles of parallelogram are equal ] ZBAD + ZADC = 180 ° ZBDC ZBDC = 30 ° .. ADC ZBAD + ZADB + ZBDC - 110 ° + 40 ° + ZBDC = 180⁰ 70 = 0 - 110⁰ 180⁰ 150⁰ 40 ° + 30 ° 70 ° ADC = ZABC = 70⁰ of parallelogram are equal ] .. BAD = 110 ° , DCB = 110⁰ , ADC 70 ° and DCB + ADC - 180 ° [ Adjacent angle [ Sum of [ Opposite ZABC [ Opposite angles = U 100 100+

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