Question

In the given figure, ABCD is a parallelogram, ∠OAD =40°, ∠OAB = 35° and
∠COD =65°. Find ∠ODC.

Answer 1

Answer:

Angle cod is 65 so so angle aob is 65( vertical opposite angle)

angle bac is35

so 35+65+dba=180 angle sum of triangle oab

so dba is 80

now second bdc is equal to dba so bdc is 80

dac is equal to acb so acb is 40

in triangle obc

angle acb +angle cob +angle dbc is 180

angle cob is found by linear pair i.e. 65+x is 180 so x is 115

115 +40+x is 180

x is 25 angle cbd is 25

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