Question

in the given figure ABCD is a parallelogram prove that AB=2BC

Answer 1

IN A // GM THE OPPOSITE SIDES ARE // TO EACH OTHER.
SO, AB// DC
SO, < EAB = < DEA ( ALTERNATE ANGLES )
AGAIN, < EAB = < DAE
SO, < DAE = < DEA
SO, AD = AE ( SIDES OPPOSITE TO EQUAL ANGLES OF A TRIANGLE ARE EQUAL)
ALSO,
AB// DC
SO, < EBA = < BEC = < EBC
SO, EC = BC
ALSO, AD = BC ( OPPOSITE SIDES OF A // GM ARE EQUAL)
SO, ED = BC AND EC = BC
SO, ED = EC
NOW,
DC = ED + EC
= BC + BC
= 2BC
AB = DC = 2BC
AB = 2BC
SO, PROVED AB = 2BC

Answer 2

Step-by-step explanation:

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