Question

In the given figure ABCD is a parallelogram such that triangle AEB congruent to triangle CFD . Prove that angle DAE = angle BCD​

Answer 1

Answer:

because it is a parallelogram

Answer 2

I think it must be BCF not BCD at last. According to this.

Answer:

BAF = FCD = x (Angles of congruent triangles are equal)

DAB=BCD (Opposite Sides of a Parallelogram are equal)

BAF+DAE = BCF+FCD

x + DAE = BCF+x

x will cancel x

Therefore, DAE = BCF

Hence, proved....