Question

In the given figure, ABCD is a parallelogram , where CE is perpendicular AB produced and BF is perpendicular to AD.
i) If AB= 30cm, CE= 14cm and BF= 20cm, then find AD.​

Answer 1

Answer:

AD = 21 cm

Step-by-step explanation:

(1)

Area of a parallelogram = (1/2) * Base * Altitude

= (1/2) * AB * CE

= (1/2) * 30 * 14

= 210 cm^2

(ii)

Area of a parallelogram = (1/2) * AD * BF

= (1/2) * AD * 20

= 10 * AD

On equating both, we

=> 10 * AD = 210

=> AD = 21 cm

Therefore, AD = 21 cm

Hope it helps!

Answer 2

Answer:

$\huge{\underline{\mathfrak{Solution\::}}}$

At first,

Area of parallelogram = 1/2 × base × altitude

Area = 1/2 × AB × CE

Area = 1/2 × 30 × 14

★$Area = 210 {cm}^{2}$★

Secondly,

Area of parallelogram= 1/2 × base × altitude

Area = 1/2 × AD × BF

Area = 1/2 × AD × 20

★$Area = 10AD{cm}^{2}$★

Equaling both we get :

$10AD{cm}^{2}=210{cm}^{2}$

Or, 10AD = 210

Or, AD = 210/10 cm

★ AD = 21 cm★

$\large\boxed{AD=21\:cm}$

Hope it helps you ♥ ♥ ♥