Question

in the given figure ABCD is a quadrilateral in which AB is parallel to DC and AD is parallel to BC prove that ADC is equal to ABC

Answer 1

ANSWER

To prove : ABCD lies on a circle i.e they are concyclic.

Join AC and BD .

Now in ∆ADC and ∆BDC,

AD = BC (given)

∠ADC =∠BDC (given)

DC= DC (common)

∆ADC≅∆BDC ( SAS congruency)

∠DAC =∠DBC ( by CPCT )

Hence the angle made by a segment on the other part of the circle are equal.

Hence A,B,C,D must lie on a circle.

Answer 2

Answer:

in foto

Step-by-step explanation:

i am writing in easy method

in hard method u use congruence