In the given figure ABCD is a quadrilateral in which AC =24 cm ,BL perpendicular AC and DM perpendicular AC such that BL=8cm and DM=7 . find the area of the quadrilateral ABCD
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The correct answer is 180 cm2
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area of triangle adm = 1/2×b ×h
1/2×24×7=84sq cm
area of triangle abc = 1/2×b×h
=1/2×24×8=96sq cm
therefore area of quadrilateral abcd=a(adm)+a(abc)
=84+96
=180sqcm
Mrunal23:
can u mark it as brailiest
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