In the given figure, ABCD is a quadrilateral in which
BC = 9cm, AD = 25cm, DC = 12cm and
LABD = LBCD = 90°
Calculate the length of AB.
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Answer:
△BDC,
∠BCD=90
∘
Thus, BD
2
=BC
2
+CD
2
(Pythagoras theorem)
BD
2
=12
2
+3
2
BD
2
=144+9
BD=
153
Now, In △ABD, ∠ABD=90
∘
AD
2
=BD
2
+AB
2
13
2
=(
153
)
2
+AB
2
169=153+AB
216=AB
2
AB=4 cm
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