Question

In the given figure. ABCD is a quadrilateral in which BD = 14 cm. AL is perpendicular to BD.CM is perpendicular to BD such that AL = 6 cm and CM = 8 cm. Find the area of quad. ABCD
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Answer 1

Answer:

98 cm²

Step-by-step explanation:

area of ABCD = Area of triangle ABD +BCD

= 1/2( 14*6) + 1/2(14*8)

= 42+ 56 =98cm²

Answer 2

hello mate

Area of ABCD=area of ABD+Area of BCD

=

$1 \div 2 \times base \times height + 1 \div 2 \times base \times heght$

=1÷2×14×6+1÷2×14×8

=7×6+7×8

=42+56

=

${98cm}^{2}$

I hope it helps u ❣❣