Question

In the given figure , ABCD is a quadrilateral inscribed in a circle diagonals of the quadrilateral are joined. If ADB = 40° and. BAC = 50° , find the ABC​

Answer 1

Answer:Given- O is the centre of a circle.  

AOC

&  

BOD

  are two diameters. ∠CAD=60  

o

.

To find out ∠BCD=?

Solution- We join AC &  BD &  BC. Now OA, OC & OD, OB are radii of the given circle since  they belong to the diameters AC &  BD respectively.

∴OA=OC=OD=OB.

Again, BC subtends ∠CDB &  ∠CAB to the circumference of the given circle. ∴∠CAB=∠CDB=25  

o

 since angles, subtended by a chord of a  circle to its circumference, are equal. Now ABCD is a cyclic quadrilateral.

∴∠DAB+∠DCB=180  

0

 

∴∠BCD=95  

0

 

Ans- Option D.

Step-by-step explanation:

Answer 2

Answer:

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