Question

In the given figure, ABCD is a quadrilateral-shaped field in which
diagonal BD is 36 m, AL ⊥ BD and CM ⊥ BD such that AL = 19 m and CM = 11
m. Find the area of the field.

Answer 1

The given details are, AL ⊥ BD and CM ⊥ BD AL=19m, CM=11m, BD=36m By using the formula, Area (quad.ABCD) = area (△ABD) + area(△ACD) Area of triangle=1/2 × base × height ∴ Area (quad.ABCD) = (½ × BD × AL) + (½ × BD × CM) = (½ × 36 × 19) + (½ × 36 × 11) = 342 + 198 = 540m2