Math, asked by rooparavi053, 3 months ago

In the given figure, ABCD is a quadrilateral-shaped field in which diagonal BD is 36 m, AL⊥BD and CM⊥BD such that AL= 19 m and CM= 11 m. Find the area of the field.
with attachment pls

Answers

Answered by rajv08844
2

Step-by-step explanation:

The given details are,

AL⊥BD and CM⊥BD 

AL=19 m,CM=11 m,BD=36m

By using the formula,

Area(quad. ABCD) =area(△ABD)+area(△ACD)

Also, area of triangle =1/2×base×height

∴Ar.(quad.ABCD)=(1/2×BD×AL)+(1/2×BD×CM)

=(1/2×36×19)+(1/2×36×11)

=342+198

=540 m2

ITS EXPERT IN MATHEMATICS PHYSICS AND CHEMISTRY

THANK YOU

Similar questions