In the given figure, ABCD is a quadrilateral-shaped field in which diagonal BD is 36 m, AL⊥BD and CM⊥BD such that AL= 19 m and CM= 11 m. Find the area of the field.
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Step-by-step explanation:
The given details are,
AL⊥BD and CM⊥BD
AL=19 m,CM=11 m,BD=36m
By using the formula,
Area(quad. ABCD) =area(△ABD)+area(△ACD)
Also, area of triangle =1/2×base×height
∴Ar.(quad.ABCD)=(1/2×BD×AL)+(1/2×BD×CM)
=(1/2×36×19)+(1/2×36×11)
=342+198
=540 m2
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