Question

In the given figure ABCD is a quadrilateral with angle A and Angle B equal .AP and BP are bisector of angle A and Angle B respectively. if Angle C equals to 60 degree and Angle B = 40 degree .find angle APB.

Answer 1

in quadrilateral ABCD,
A + B + C + D = 360
A + B + 40 + 60 = 360
A + B = 360 - 60 - 40
A + B = 260

in ∆APB,
Both the angles are bisected
thus A + B = 260/2
A + B = 130
thus A + B + APB = 180
130 + APB = 180
APB = 180 - 130
APB = 50


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Answer 2

Answer:

50 degree

Step-by-step explanation:

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