Question

in the given figure, ABCD is a quadrilateral with angle B = 56° and angle D =104°. if angle BAD and BCD are in the ratio 2:3, find the value of x and y.​

Answer 1

Answer:

X = 100° and Y = 60°

Let angle BAD be 2x and BCD be 3x

As BAD:BCD = 2:3

=> 2x+3x=360-104-56 ( ALL ANGLES OF A QUADRILATERAL SUMS TO 360 )

5x=200

x=40°

BAD=2x=80°

BCD=3x=120°

X=180-BAD=180-80 X=100°

Y=180-BCD=180-120 Y=60°

(SUPPLEMENTARY ANGLES)

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Answer 2

Answer:

x=100,y=60

Step-by-step explanation:

2x+3x+104+56=360 (sum of all angles of quadrilateral is 360)

5x=360-104-56

5x=200

x=200/5

x=40

BAD=2X=2×40=80

BCD=3X=3×40=120

X= 180-80=100

Y= 180-120=60 ( supplementary angles)

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