Question

In the given figure, ABCD is a rectangle and AP=DQ and AR=PD. Prove that PQ=PR

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Answer 1

In ∆APR and ∆DPQ
AP = DQ (Given)
AR = PD (Given)
∠PAR = ∠PDQ (All angles of a rectangle are equal to 90°)
∆APR ≅ ∆DPQ (by SAS Congruence)
Thus PQ = PR (by CPCT)
Hence Proved

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Answer 2

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