Question

In the given figure, ABCD is a rectangle and EF perpendicular to AB. The area of the shaded part, in the given figure, is ...

Answer 1

Step-by-step explanation:

Area of the shaded region = 684 meter²

Step-by-step explanation:

Length of rectangle = 36 meter

Breadth of rectangle = 24 meter

Area of the rectangle ABCD = Length × Breadth

Area = 36 × 24

Area = 864 meter²

Now, in ΔADE

AD = 24 meter

Height, EF = 15 meter

\begin{gathered}\text{Area of triangle ADE = }\frac{1}{2}\times AD\times EF\\\\Area =\frac{1}{2}\times 24\times 15\\\\Area = 180\text{ meter}^2\end{gathered}

Area of triangle ADE =

2

1

×AD×EF

Area=

2

1

×24×15

Area=180 meter

2

⇒ Area of shaded region = Area of Rectangle ABCD - Area of ΔADE

⇒ Area of the shaded region = 864 - 180

⇒ Area of the shaded region = 684 meter²