* In the given figure, ABCD is a rectangle and EFGH is a trapezium DE=CH.
If ar(rect ABCD) = 26 cm², then ar(trap EFGH) is
(a) 52 cm2
(b) 26 cm2
(c) 39 cm2
(d) 34 cm2
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(a) 52cm2 because of 26×2=52cm2
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