Question

. In the given figure, ABCD is a rectangle, diagonals AC and BD intersect at Oand angle AOB = 60°. Find the measure of angle OAD.​

Answer 1

Answer:

As AO is perpendicular on BD so when BOA is 60° then AOD is also 60° as,

BOA + AOD = 180°

AOD = 180° - BOA

AOD = 180° - 60°

AOD = 60°

Now we take OAD and ADO as x so by area of triangle the value of angle OAD

will be

OAD + ADO + AOD = 180°

x + x + 60° = 180°

2x = 180° - 60°

2x = 60°

x = 60°/2

x = 30°

So, your answer of the measure of angle OAD is 30° .