IN THE GIVEN FIGURE ABCD IS A RECTANGLE IF AB=20CM BC=12CM AND AF:FE=3:2 THEN FIND THE LENGHT OF FE IN CENTIMETERS
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What is F and E?
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according to the data given above,
AB = 20 cm
BC = 12 cm
AF:FE = 3:2
now,
let AF = 3x and FE = 2x
and ED = x
therefore,
AF + FE + ED = AD
and AD = BC = 12 cm
since opposite sides of a rectangle is equal.
therefore,
3x + 2x + x = 12
5x + x = 12
6x = 12
x = 12 / 6
x = 2
therefore value of FE =2x = 2 * 2 = 4
therefore FE = 4 cm
i hope that my answer will help u...................................^_^
AB = 20 cm
BC = 12 cm
AF:FE = 3:2
now,
let AF = 3x and FE = 2x
and ED = x
therefore,
AF + FE + ED = AD
and AD = BC = 12 cm
since opposite sides of a rectangle is equal.
therefore,
3x + 2x + x = 12
5x + x = 12
6x = 12
x = 12 / 6
x = 2
therefore value of FE =2x = 2 * 2 = 4
therefore FE = 4 cm
i hope that my answer will help u...................................^_^
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