Question

IN THE GIVEN FIGURE ABCD IS A RECTANGLE . IF AREA OF TRIANGLE EFC IS 16 CM^2 AND AREA OF TRIANGLE BFC IS 20 CM^2 THEN FIND THE AREA OF QUADRILATERAL ADEF ?



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Answer 1

As, we know, perimeter of a parallelogram ABCD=AB+ BC+CD+ AD

96 =18+ AD + 18+ AD

96=36+2AD

2AD=60

AD= 30cm

AD BC= 30 cm

[AD=BC]

So.

Now, area of parallelogram ABCD Basex Corresponding height

270= AB x DE

270= 18 xDE 270 =DE

18 DE= 15m

Also, area of parallelogram ABCD AD×BF

270= 30x1

I= 270 30

1=9m

Hence, altitudes l = 9m and m= 15m