In the given figure. ABCD is a rectangle in which AB =
40 cm and BC = 25 cm. If P, Q, R, S be the midpoints
of AB, BC, CD and DA respectively, find the area of
the shaded region.
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Answer:
500 cm^2
Step-by-step explanation:
QC = 25/2 = 12.5 cm
CR = 40 / 2 = 20 cm
area of ΔQRC = 1/2 * 20 * 12.5
= 125 cm^2
∴125 x 4 = 500 cm^2
∴40 x 25 - 500 = 500cm^2
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