In the given figure, ABCD is a rectangle in which AB = 40 cm and BC = 25 CM. If p, q, r, s be the midpoints of AB, BC, CD and DA respectively, find the area of the shaded region
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Answer: Area of rectangle=l*b=40*25=1000cm2
p is the midpoint of AB
PB=1/2*40=20cm
q is the midpoint of BC
BQ=1/2*25=12.5cm
Area of triangle PBQ=1/2*b*h
Area of triangle PBQ=1/2*20*12.5
Area of triangle PBQ=10*12.5
Area of triangle PBQ=125cm2
All four triangles are equal
Area of 4 triangle =125*4
Area of 4triangle =500cm2
Area of shaded region =1000-500
Area of shaded region =500cm2
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