Question

In the given figure,ABCD is a rectangle inscribed in a circle.The circumference of the circle is 110 cm and AB = 21cm.Find the length of BC.​

Answer 1

Answer:

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Answer 2

$\huge \purple {\mathfrak{ \underline{ \underline{ \: correct \: question: - }}}}$

The given figuer shows a rectangle ABCD inscribed in a circle as shown alongside.

If AB=28 cm and BC=21 cm, find the area of the shaded portion of the given figure.

$\huge \purple {\mathfrak{ \underline{ \underline{ \: required \: answer: - }}}}$

374.5cm

$\huge \purple {\mathfrak{ \underline{ \underline{to \: find: - }}}}$

Arєα σf ѕhαdєd pσrtíσn = αrєα σf círclє - αrєα σf ABCD

$\implies{ \mathtt{ = \pi \times ( \frac{AB}{2} {)}^{2} \: - AB \times \: BC}}$

$\implies{ \mathtt{AC = \sqrt{A {b}^{2} + b {c}^{2} } = \sqrt{2 {8}^{2} } + 2 {1}^{2} = 35cm}}$

$\implies{ \mathtt{area \: of \: shaded \: portion = }}$

${ \mathtt{ (\frac{22}{7} \times \frac{35}{2} \times \frac{35}{2}) - (28 \times 21)}}$

$\mathtt{ = 962.5 - 588}$

${ \mathtt{ = 374.5cm}}$