Question

in the given figure ABCD is a rectangle The radius of the semicircles drawn on AD and BC as diameter and radius of circle drawn in be​

Answer 1

Answer:

given AB=14cm BC=AD=7cm

we know that the area of rectangle =l*b

area of semicircle is =π×r2/2

here the radius of the big semicircle=14/2=7cm

here the radius of small semi circle=7/2

area of shaded region=area of ABCD+2×area of small semicircle-area of big semicircle

( l×b)+21/2πr2-1/2πr2

(14×7)+2×/2×22/7×7/2×7/2-1/2×22/7×7×7

98+38.5-77=59.5cm2