in the given figure ,ABCD is a rectangle where AB=8 cm,BC=6 cm and diagonal bisect each other at O . find area of the down most triangle
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Answer:
Given : AB=8cm BC=6cm
AC=
8
2
+6
2
=10
AO=
2
10
=5
S=
2
5+5+8
=9
Area of ΔAOB=
S(S−a)(S−b)(S−c)
=
9(9−8)(9−5)(9−5)
=
9×1×4×4
=3×4
Area of ΔAOB=12 sq. units.
Step-by-step explanation:
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