Question

in the given figure ABCD is a rectangle who is diagonals is AC and BD intersect each other at oh if angle OAB is equal to 28 degree find angle OBC

Answer 1

Answer:

62 degree

Step-by-step explanation:

<BAD = 90° ( ABCD is a rectangle)

<CAD = <BAD-28

= 90 - 28

= 62°

<CAD = 62°

Now,

In Triangle CAD and DBC

<ADC = <BCD (each 90°)

AD = BC (Opposite sides of rectangle)

CD =DC (common)

So, Triangle CAD congurent Triangle DBC

(By S. A. S criteria)

<DBC = <CAD (C. P. C. T)

< DBC = 62°

<OBC = 62°

Answer 2

Heya _____

Solution ______

< BAD = 90° ( ABCD rectangle )

< CAD = < BAD - 28°

90°-28°= 62°

Now about triangle ______

Triangle CAD and DBC

<ADC = <BCD ( each 90°)

AD = BC opposite side

CD = DC common

So both r congruent ____

< DBC = <CAD ( cpct )

< DBC = 62°

So.... <OBC = 62°

Thank you