in the given figure ABCD is a rectangle with length AC= 36 and breadth CA =24 meters in the triangle A B G, F G is perpendicular to AB and F G= 15 C ED is a semicircle with CD as its diameter calculate the area of the shaded portion
Answers
Answer:
hello...
bro.....
this is your answer.......
given
AC is equal to 36
AD is equals to 24
as it is a right angle triangle according to Pythagoras formula
{ac}^{2} = {ad}^{2} + {dc}^{2}
(36)^2 = (24)^2 + (dc)^2
dc=
\sqrt{720} = 26.8
area of the triangle is= 1/2× base(AB)× height(AD)
= 201
area of rectangle =length(AB) × breadth(AD)
=643.2
area of the semicircle is equal to
\pi {r}^{2} \div 2
r = 26.8/2 = 13.4
area is equale to 282.05
total area of the figure is =
area of the triangle + area of the rectangle + area of the semicircle.
= 201+643.2+282.05
=1126.25
hope this will help you mate......
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