Question

In the given figure, ABCD is a rectangle with length (p^2q-5) and breadth (q^2+4p)
Find the area of shaded triangle PAB.
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Answer 1

Answer:

area of rectangle = (p^2q-5)(q^2+4p)

Since they are between same parallels and on common base AB, area of triangle is half that of rectangle = (p^2q-5)(q^2+4p)/2