Question

in the given figure abcd is a rhombsus AO IS 4CM AND DO IS 3CM THEN FIND THE PERIMETERBOF THE RHOMBUS​

Answer 1

Answer:20 cm

Step-by-step explanation:1~ as we know diagonals of rhombus bisect each other at 90° therefore in triangle AOD by PYTHAGORAS theorem AD*2=DO*2+AO*2 is AD*2=3*2+4*2 AD=√9+16 AD=√25=5 perimeter of rhombus =4×side =4×5=20cm

Answer 2

Step-by-step explanation:

this is the answer

the side of the rhombus is 5 cm and all sides are equal

if u like it pls mark s brainliest answer pls