Math, asked by spyaarya, 11 months ago

in the given figure, ABCD is a rhombus and angle ACB=45° find angle ADC​

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Answered by omjeechoudhary30
5

Answer:90°Step-by-step explanation:since AB||BCso,DAC=ACB=45° (V.O.A)now, AD=CDso,ACD=DAC=45°SO,ADC+DAC+ ACD=180 SO,ADC+45°+45°=180ADC =180-90= 90

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