In the given figure, ABCD is a rhombus. Find the values of x, y and z.
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the diagonal of a rhombus are bisect each other at right angle
so,AO=OC
x=8cm
BO=OD
y=6cm
by Pythagoras theorem TriangleAOB
(AB)sq.=(Ao)sq+(BO)sq.
(AB)sq.=(8)sq.+(6)sq.
(AB)sq.=64+36
(AB)sq.=100
AB=√100cm
AB=10m
Hence,x=8cm,y=6cmand z=10cm
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