In the given figure ABCD is a rhombus if angle oab is equal to 35° then find the value of x
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· Then CD = CB. => ∠CBD = x°. ∠BCD = ∠BAD = 70°. (Opposite angles of rhombus) ∴ x + x + 70° = 180° (sum of angles of ∆ equal to 180°) 2x = 110° x = 55°. ⇒ ∠CDB = 55°. Please log in or register …
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