Question

In the given figure, ABCD is a rhombus. Then, AD²+ BD² =
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Answer 1

heya your answer is

diagonals of rhombus bisect each other at 90 degrees.

OA = 1/3 AC

OB = 1/2 BD

AND ANGEL AOB =90

IN RIGHT TRIANGLE AOB USING PULYTHAGOREN TRIPLET

AB^2 = OA ^2 + OB^2

AB^2 = 1/2 AC^2 +1/2 BD^2

AB ^2 = 1 / 4 [AC^2 +BD ^2]

4AB ^2 = AC^2 + BD^2.....

THANKS

Answer 2

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