In the given figure,ABCD is a rhombus, then find the value of x-y.
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Answer:
35°
Step-by-step explanation:
Diagonals of a rhombus bisect each other at 90°
So, x = 90°
In triangle AOB, (O is the point where the diagonals are meeting)
Angle AOB = 90°
Angle OAB = 35°
Sum of three angles of a triangle = 180°
Angle AOB + Angle OAB + Angle OBA = 180°
90 + 35 + Angle OBA = 180
Angle OBA = 180 - 125
Angle OBA = 55°
So, y = 55° (alternate angles)
x - y = 90 - 55 = 35°
Hope it helps you:)
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