Question

In the given figure, ABCD is a square and
BX = BY. Prove that <DXC = <DYA.​

Answer 1

Step-by-step explanation:

if

BX=BY

alternarively

DY=DX

also

AY=CX

and

AD=DC since it is a square

since

FROM here

triangle ADY=XDC

SO <DYA=,<DXC