Question

in the given figure ABCD is a square and triangle ABC is an equilateral triangle prove that triangle ABC is congruent to triangle BPC and angle DBC equals to 15 degree​

Answer 1

mistake in data

Step-by-step explanation:

There looks some mistake in data

Given ABCD is a square

=> AB = BC = CD = AD = x

AC² = AB² + BC²

=> AC² = x² + x²

=> AC² = 2x²

=> AC = √2x

now given ABC is an equilateral triangle

=> AB = BC = AC

=> AC = x

but AC = √2x

x ≠ √2x

Hence Mistake in Data

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