Question

In the given figure , ABCD is a square and triangle DEC is an equilateral triangle. Prove that : I)- triangle ADE congruent to triangle BCE ii)- AE = BE
Pls answer fast it’s urgent

Answer 1

Answer:

Did you mean: In the given figure , ABCD is a square and triangle DEC is an equilateral triangle. Prove that : A)- triangle ARE congruent to triangle BCE

In the given figure , ABCD is a square and triangle DEC is an equilateral triangle. Prove that : I)- triangle ADE congruent to triangle BCE

Results in English

दिए गए चित्र एबीसीडी में एक वर्ग और त्रिकोण दिसम्बर एक समभुज त्रिकोण साबित है कि मैं) - त्रिकोण एडीई त्रिभुज bce के लिए अनुकूल

हिन्दी में नतीजे

Search Results

Featured snippet from the web

Given: ABCD is a square and ∆DEC is an equilateral triangle. (iv) AP is the perpendicular bisector of BC. Given: ∆ABC and ∆DBC are two isosceles triangles on the same base BC and vertices A and D are on the same side of BC. ... (iv) AP is the perpendicular bisector of BC.